Taken from a post on WOV; "Advantage play in craps involves distributing bets amongst the different proposition bets and place bets in an attempt to change the game into something the player is expected to win. Once a reliable combination of bets is found, it's usually followed up with negative progressive betting. Once a relatively small profit is made, the advantage player leaves the table. One example would be betting 10 on the field, and 5 on the any7. For that next roll, you'd have a 22:14 advantage over the casino. If a 5, 6 or 8 comes out, you lose and you up your bets in a fashion to recover your losses. The Martingale system or whatever variation that is added is all but useless in a negative expectation game, but this has been modified into a game where there are more winning combinations than losing combinations, so chasing losses isn't actually all too absurd." I, of course would hop sevens for $6 for a lower vig. So what do you think of this and would it be possible to DI this in any way?

OP scenario: Win $15 on 2 or 12 (assumes 2x on both numbers) Lose $15 on a 5, 6 or 8 Win $5 on 3, 4, 9, 10, 11 Win $10 on 7 "Big" loser ($15) on 14 rolls (5, 6, 8) compared with "big" winner ($15) on 2 rolls (2, 12). Decent win ($10) on 6 rolls (7). If one decides to employ this betting system, I'm in agreement with DeMango -- 7s hopping is the way to go, for $3 (based upon $10 Field Bet). If a 5, 6 or 8 hits, the bettor can "recover" a $13 loss ($10 + $3) with 2 hits on a non-2/12 Field number (i.e., 3,4, 9, 10, 11). In the OP scenario with a $5 Any 7, 3 such hits would be required to recover the $15 loss.